P__P04 2025-03-25

Po =

\(P_o=P_0+\ \dots\ +P_{n-1}\)

Prp =

\(P_{rp}=\dfrac{1}{\dfrac{1}{P_0}+\ \dots\ +\dfrac{1}{P_{n-1}}}\)

Ph =

\(P_h=\dfrac{n}{\dfrac{1}{P_0}+\ \dots\ +\dfrac{1}{P_{n-1}}}\)

Pm =

\(P_m=\sqrt[n]{P_0\cdot\ \dots\ \cdot P_{n-1}}\)

Psz =

\(P_{sz}=\dfrac{P_0+\ \dots\ +P_{n-1}}{n}\)

Pn =

\(P_n=\sqrt{\dfrac{{P_0}^2+\ \dots\ +{P_{n-1}}^2}{n}}\)

	P₀ =
	P₁ =
	P₂ =
	P₃ =
	P₄ =
☺ ☺ P: ☺ ☺

Po =		\(P_o=P_0+\ \dots\ +P_{n-1}\)
Prp =		\(P_{rp}=\dfrac{1}{\dfrac{1}{P_0}+\ \dots\ +\dfrac{1}{P_{n-1}}}\)
Ph =		\(P_h=\dfrac{n}{\dfrac{1}{P_0}+\ \dots\ +\dfrac{1}{P_{n-1}}}\)
Pm =		\(P_m=\sqrt[n]{P_0\cdot\ \dots\ \cdot P_{n-1}}\)
Psz =		\(P_{sz}=\dfrac{P_0+\ \dots\ +P_{n-1}}{n}\)
Pn =		\(P_n=\sqrt{\dfrac{{P_0}^2+\ \dots\ +{P_{n-1}}^2}{n}}\)

document.write( SzHuEnSzSz( 'Teljesítmények összege és közepei', 'Sum and means of powers' ) );