Egysoros tekercs menetszáma - körméretből, hosszból és induktivitásból

μr =
	dh =	\(l_a/(N+0,5)=l_k/(N+1)\)
	Ah =
	=
=
	la =	\(d_h\cdot(N+0,5)\)
	=
L =				←d,L
☺
da[0..4] =
N0 =				\(L_0=\dfrac{\mu_r\cdot\mu_0\cdot {d_a}^2\cdot N^2}{1,7593\cdot l_a+0,50266\cdot d_a}\)
dh0 <=
da0 =
db0 =
la0 =
lk0 =
lh0 =				\(l_h=\sqrt{\left(N\cdot\pi\cdot d_a\right)^2+{l_a}^2}\)
N1 =				\(L_1=\dfrac{\mu_r\cdot\mu_0\cdot {d_a}^2\cdot N^2}{1,2566\cdot l_a+0,56549\cdot d_a}\)
dh1 <=
da1 =
db1 =
la1 =
lk1 =
lh1 =
N2 =				\(L_2=\dfrac{\mu_r\cdot\mu_0\cdot {d_a}^2\cdot N^2}{1,2767\cdot l_a+0,57454\cdot d_a}\)
dh2 <=
da0 =
db2 =
la2 =
lk2 =
lh2 =
N3 =				\(L_3=\mu_r\cdot\mu_0\cdot k\cdot d_a\cdot N^2\) \(0,01\le\dfrac{d_a}{l_a}\le 1\rightarrow k=0,6398\cdot\left(\dfrac{d_a}{l_a}\right)^{0,912}\) \(1\lt\dfrac{d_a}{l_a}\le 100\rightarrow k=0,6517+0,5443\cdot\ln\left(\dfrac{d_a}{l_a}\right)\)
dh3 <=
da3 =
db3 =
la3 =
lk3 =
lh3 =

\(L_0=\dfrac{d_a\cdot N^2}{0,14\cdot\dfrac{l_a}{d_a}+0,04}\)	[da] = [l] = cm; [L0] = cm	Molnár, Jovitza: Rádiósok könyve, 85. oldal ( reprint 1994. ).
\(L_1=\dfrac{d_a^2\cdot N^2}{100\cdot l_a+45\cdot d_a}\)	[da] = [l] = cm; [L1] = μH	Rádióamatőrök kézikönyve 1978. 1.28.
\(L_2=\dfrac{r_a^2\cdot N^2}{10\cdot l_a+9\cdot r_a}\)	[da] = [l] = inch; [L2] = μH	Wheeler képlet
\(L_3=k\cdot d_a\cdot N^2\) \(0,01\le\dfrac{d_a}{l_a}\le 1\rightarrow k=8,04\cdot 10^{-3}\cdot\left(\dfrac{d_a}{l_a}\right)^{0,912}\) \(1\lt\dfrac{d_a}{l_a}\le 100\rightarrow k=8,19\cdot 10^{-3}+6,84\cdot 10^{-3}\cdot\ln\left(\dfrac{d_a}{l_a}\right)\)	[da] = [l] = cm; [L3] = μH	HE 1993-03-101.